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Drupal: How to create a View that shows results only from the current node

Posted Sat, 02/06/2010 - 1:27am

Let's say you want to create a Views block that shows on a bunch of different pages/nodes that have multiple (imagefield) images per page, and you want the block to dynamically display ONLY the images from the particular node you're on--and not display images from other nodes.

This is how you would do it:

1. Create your view as you normally would.
2. Add "Node: Nid" under "Arguments".
3. Select "Provide Default Argument" under "Action to take if argument is not present:"
4. Select "Node ID from URL" under "Default argument type:"
5. Leave everything else as is...
6. Hit "Update" and then "Save"... and you're done.

Comments

Thanks

by Jef - 04/09/2010 - 5:00am

Thank you for that!

thanks dude

by Anonymous - 10/30/2010 - 11:45pm

thanks dude

thanks dude

by Evgeny - 10/30/2010 - 11:46pm

thanks dude

Thanks for the the post! That

by Anonymous - 11/02/2010 - 1:25am

Thanks for the the post! That was Hilarious!!

Nmhdheeslbcdahtthr

by Duren6250 - 12/09/2010 - 11:28pm

Nmhdheeslbcdahtthr ejdwvyyacoo

Thank you! That was exactly

by Lisa - 01/27/2011 - 5:23am

Thank you! That was exactly what I was looking for! :)
What if I wanted to show the view inside the node? As I understand it it should be possible using views attach but I can't quite understand how it works…

this works well, but what if

by Anonymous - 05/12/2011 - 3:48pm

this works well, but what if you have automatic alias turned on. I tried using Node: title but it doesn't take into account the directory path.

Thank you this worked for me!

by Anonymous - 06/17/2011 - 10:10am

Thank you this worked for me!

awdfsf

by dasds - 06/19/2011 - 11:40pm

awdfsf

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